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  • J.R.Chen's work on Goldbach conjecture@袁运甫
  • Research

    学而不思则罔,思而不学则殆

    说的好像很有道理

    Sieves of typos: let n be the number of proof-reading been made. Let T(n) be the amount of typos after the n-th proof-reading.

    T(n)/T(0)=(1-1/2)(1-1/3)(1-1/4)...(1-1/(n+1))

    It is never ZERO unless T(0)=0 which is impossible.